Kv, Kt and Ke: one motor constant in three units
Motor datasheets list a speed constant in rpm per volt, a back-EMF constant in volts per krpm, and a torque constant in mN·m or oz·in per amp. They look like three separate specifications. They are one number in different units, and the only real trap is which volts and which amps the number was measured in. This article shows why the constants are linked, how to convert them for brushed DC and BLDC motors, where the factors of √3, √2 and 1.5 come from, and how to use them to choose a winding for a robot joint. Two real datasheets are worked through along the way: the maxon RE 40 brushed DC motor and the ODrive D5065 270KV brushless motor.
- In SI units Kt (N·m/A) and Ke (V·s/rad) are numerically equal, and Kv is their inverse (rad/s per volt). Reason: E·I = T·ω.
- Brushed DC: Ke = Kt = 9.549 / Kv with Kv in rpm/V. Speed constant [rpm/V] × torque constant [mN·m/A] = 9,549.
- BLDC / PMSM, sinusoidal (FOC) drive: line-to-line peak Ke = 9.549 / Kv; Kt per peak phase ampere = 8.27 / Kv; Kt per RMS phase ampere = 11.70 / Kv.
- Mixing conventions costs 15 % (peak phase vs. DC-link amps) or 41 % (peak vs. RMS). Always record which convention a number uses.
- Rewinding with N times the turns multiplies Ke and Kt by N, divides Kv by N and multiplies resistance by N². The motor constant Km = Kt/√R (for a three-phase motor, Kt,pk/√(1.5Rph)) does not change: Kv picks a voltage and current level, Km measures how good the motor is.
One constant, three names
A motor converts electrical power into mechanical power. On the electrical side that power is the back-EMF E times the current I. On the mechanical side it is torque T times angular speed ω. Resistive heating, friction and iron loss are handled separately, so the conversion itself loses nothing:
Two proportionalities are enough. Back-EMF grows linearly with speed, E = Keω, and torque grows linearly with current, T = KtI. Substituting both gives KeωI = KtIω, so the speed and current cancel:
Ke and Kt are one constant seen from the electrical side and from the mechanical side. If a datasheet shows two numbers that disagree after unit conversion, the cause is a unit or a convention, not physics. The hobby unit for Kv is rpm per volt, which is the SI value multiplied by 60/(2π) = 9.549.
| Constant | SI unit | Datasheet units | Conversion |
|---|---|---|---|
| Back-EMF constant Ke | V·s/rad | V per 1000 rpm | Ke [V/krpm] = 104.72 × Ke [V·s/rad] |
| Torque constant Kt | N·m/A | mN·m/A, oz·in/A | × 1,000 for mN·m/A • × 141.61 for oz·in/A |
| Speed constant Kv | rad/s per V | rpm/V | Kv [rpm/V] = 9.549 / Ke [V·s/rad] |
| Product | — | rpm/V × mN·m/A | = 30,000/π = 9,549.3 |
| US servo shortcut | — | oz·in/A and V/krpm | Kt [oz·in/A] = 1.352 × Ke [V/krpm] |
maxon calls these the speed constant kn (rpm/V), the torque constant kM (mN·m/A) and the generator constant kG (V per 1000 rpm), and notes that kn is essentially the inverse of kM and kG = 1/kn [1]. The 9,549 product above is not a vendor number: it is 60/(2π) × 1000, the unit conversion that makes the SI equality hold.
Brushed DC motor: the simple case
A permanent-magnet brushed motor has one winding and one current, so there is no convention to choose. The armature voltage equation and the torque equation are
Eliminate the current and the motor becomes a straight line from no-load speed to stall torque:
This is where Kv gets its meaning: it is the no-load speed per volt, ignoring the small R·I0 drop. The slope depends on R and Kt, not on the supply voltage, so raising the voltage slides the whole line to the right without changing its steepness. The quantity Km = Kt/√R, the motor constant, sets that slope and is the number that says how much torque you get per square root of watt of copper loss.
A real datasheet: maxon RE 40 (part 148877)
The maxon RE 40 is a well-known 150 W graphite-brush motor of the kind used in robotics and laboratory equipment. Its datasheet [2] lists, at 48 V, a torque constant of 60.3 mN·m/A, a speed constant of 158 rpm/V, a terminal resistance of 1.13 Ω and a no-load current of 68.6 mA. Everything else in the table can be rebuilt from just those few numbers plus the supply voltage, which is a good way to check that you have understood them.
| Datasheet entry | Published | Computed | From |
|---|---|---|---|
| Speed constant | 158 rpm/V | 158.4 rpm/V | 9549 / 60.3 |
| No-load speed | 7,590 rpm | 7,589 rpm | (V − R·I0) / Ke |
| Stall current | 42.4 A | 42.5 A | V / R |
| Stall torque | 2,560 mN·m | 2,557 mN·m | Kt(Istall − I0) |
| Speed/torque gradient | 2.97 rpm/mN·m | 2.97 rpm/mN·m | R / (KeKt) = 1/Km² |
| Max. efficiency | 92 % | 92.1 % | (1 − √(I0/Istall))² |
| Nominal current at 187 mN·m | 3.17 A | 3.17 A | T/Kt + I0 |
| Nominal speed at 187 mN·m | 7,000 rpm | 7,034 rpm | (V − R·I) / Ke |
All eight rows agree to the rounding of the datasheet. Only three motor-specific numbers are doing the work: Kt (= Ke), R and I0. The speed constant is not an independent specification; it is the torque constant read in other units, and the datasheet's 158 rpm/V and 60.3 mN·m/A multiply to 9,527, within 0.3 % of 9,549.
At the nominal point the motor draws 3.17 A and delivers 138 W from 152 W, an efficiency of 90.5 %. The best efficiency of 92 % occurs at only 1.71 A, or 99 mN·m, because the two losses are balanced when R·I² equals the no-load loss. A motor at its best efficiency is lightly loaded and fast, far from the 2.56 N·m stall point, which is why a small fast motor behind a gearbox often beats a large slow one.
Two caveats. First, the equality Kt = Ke describes a permanent-magnet motor; in a wound-field motor both constants scale with the field flux, so they change with field current. Second, brush voltage drop shifts the no-load speed slightly, so measure Ke by turning the motor as a generator on open circuit rather than from V/ω0.
BLDC and PMSM: the same balance, with conventions
A three-phase machine obeys the same power balance. The difference is that there are three voltages and three currents, each of which can be quoted as peak or RMS, per phase or line-to-line. Every factor of √3, √2 or 1.5 in this section comes from that bookkeeping, not from new physics.
Let ψ be the peak permanent-magnet flux linkage of one phase, p the number of pole pairs and ωm the mechanical speed. The phase back-EMF is ea = −pωmψ sin θe, the same expression used in the winding sequence article. Its peak is pψωm, and the flux linkage itself comes from the winding: ψ = kw·N·Φ1, the winding factor times the series turns times the fundamental flux per pole.
Datasheets and ESCs quote the voltage between two terminals. For a star-connected winding the line-to-line peak back-EMF is √3 times the phase value:
The torque constant follows from the balanced three-phase power at the terminals. With current in phase with the back-EMF (the q-axis, id = 0), the power is √3 × VLL,rms × Irms. In peak quantities that is (√3/2) × ELL,pk × Ipk. Setting it equal to Tω gives
Because the derivation uses terminal quantities, it holds for a delta-connected winding as well as a star. Measure at the terminals and the star/delta question disappears.
| Constant | Definition | From Kv [rpm/V] | Example, Kv = 270 |
|---|---|---|---|
| Ke, line-to-line peak | √3 · pψ | 9.549 / Kv | 0.0354 V·s/rad |
| Ke, phase peak | pψ | 5.513 / Kv | 0.0204 V·s/rad |
| Ke, line-to-line RMS | √3 · pψ / √2 | 6.752 / Kv | 0.0250 V·s/rad |
| Ke, phase RMS | pψ / √2 | 3.898 / Kv | 0.0144 V·s/rad |
| Kt per peak phase amp (FOC) | 1.5 · pψ | 8.270 / Kv | 0.0306 N·m/A |
| Kt per RMS phase amp | 1.5√2 · pψ | 11.70 / Kv | 0.0433 N·m/A |
| Kt per DC-link amp, six-step | ≈ Ke,LL (trapezoidal EMF) | 9.549 / Kv | 0.0354 N·m/A |
The last row applies to ideal six-step drive of a motor with flat-topped (trapezoidal) back-EMF: only two phases conduct, the voltage across them is the flat line-to-line value, and ELL·Idc = Tω gives Kt = Ke,LL just as in the DC motor. A motor with sinusoidal back-EMF driven by ideal 120° current blocks gets (3/π) × Ke,LL = 0.955 × Ke,LL per ampere of block amplitude, and torque ripple at six times the electrical frequency.
The ratio between the two most common quotes is 9.549/8.270 = 2/√3 = 1.155. A torque estimate made with 9.549/Kv for a controller that regulates peak phase current is therefore 15 % too high; one made with peak where RMS was meant is off by √2. FOC firmware that regulates iq in amplitude-invariant form uses peak phase current, and a multimeter in AC mode reads RMS, so check the convention in your controller's documentation before trusting a number.
A real datasheet: ODrive D5065 270KV
ODrive's motor page [3] lists the D5065 270KV, a 14-pole (7 pole-pair) outrunner popular in hobby and research robot actuators. Its entries are: Kv 270 rpm/V, torque constant 0.031 N·m/A, phase resistance 39 mΩ and phase inductance 16 µH (both phase-to-neutral), 45 A continuous in free air and 85 A for 3 seconds. The footnotes matter as much as the numbers: "All voltage units are line-line amplitude" and "All current units are phase amplitude." That is exactly the line-to-line peak Ke and peak-phase-current Kt of the table above, so the published torque constant should equal 8.27/Kv. The page lists two sibling motors in the same format, which gives three checks:
| Motor | Kv (rpm/V) | Published Kt (N·m/A) | 8.27 / Kv | Difference | 9.549 / Kv | Difference |
|---|---|---|---|---|---|---|
| D5312s 330KV | 330 | 0.025 | 0.0251 | +0.2 % | 0.0289 | +16 % |
| D5065 270KV | 270 | 0.031 | 0.0306 | -1.2 % | 0.0354 | +14 % |
| D6374 150KV | 150 | 0.055 | 0.0551 | +0.2 % | 0.0637 | +16 % |
The 8.27/Kv column matches all three published values to within their two-figure rounding. The 9.549/Kv column, the DC-motor rule applied to a brushless motor, overstates torque per amp by 14–16 %. This is the 2/√3 factor from the previous section appearing in a real datasheet.
Starting from just Kv = 270, p = 7, Rph = 39 mΩ and the 45 A rating, you can derive the rest:
- Ke,LL = 9.549 / 270 = 0.0354 V·s/rad, which is 3.70 V line-to-line peak per 1,000 rpm.
- ψ = 0.0354 / (√3 × 7) = 2.92 mWb of flux linkage per phase.
- No-load speed is 6,480 rpm on a 24 V bus and 12,960 rpm on 48 V (before any load or field weakening).
- At 45 A continuous, torque is 1.40 N·m and copper loss is 1.5 × 45² × 0.039 = 118 W. At the 85 A peak the same constant would give 2.63 N·m and 423 W, which is consistent with a 3-second rating, and saturation, which lowers Kt at high current, would make the real figure lower.
The page itself cautions that all performance figures are approximate and depend on cooling, so treat these as first estimates.
Measuring Ke on the bench
The back-EMF test from the winding sequence article also gives Kv. You do not need a tachometer, because the electrical frequency on the scope already encodes the speed: fe = p·n/60.
- Disconnect the drive and turn the shaft at a steady speed, for example with a drill.
- Read the electrical frequency fe from the scope and compute n = 60·fe/p, then ωm = 2πn/60.
- Read the line-to-line peak voltage between two terminals. A true-RMS meter gives the RMS value, which is the peak divided by √2 for a sine wave.
- Ke,LL = Vpk/ωm, then Kv = 9.549/Ke,LL and Kt,pk = 0.866 × Ke,LL.
If the motor is turned at 1,000 rpm, the scope should show fe = 7 × 1,000 / 60 = 116.7 Hz, with ωm = 104.72 rad/s. The line-to-line peak should then be about 3.70 V (a true-RMS meter would read 2.62 V). Working back from such a reading:
This measures Ke cold and at open circuit. The torque constant under load is usually a little lower, for the reasons in the last section.
Kv is a winding choice, Km is the motor
A common belief is that a high-Kv motor is the more powerful one. It is not. Put N turns in series per phase and everything scales with N: the flux linkage ψ, and therefore Ke and Kt, grow in proportion to N; the wire cross-section shrinks as 1/N for the same slot, so resistance grows as N². Kv falls as 1/N and resistance rises as 1/Kv². The combination that does not move is the motor constant,
Kv therefore says nothing about how good a motor is. The three ODrive motors above show it:
| Motor | Kv | Kt (N·m/A) | Rph (mΩ) | Km (N·m/√W) | Torque at continuous current | Copper loss there |
|---|---|---|---|---|---|---|
| D5312s 330KV | 330 | 0.025 | 37 | 0.106 | 0.75 N·m at 30 A | 50 W |
| D5065 270KV | 270 | 0.031 | 39 | 0.128 | 1.40 N·m at 45 A | 118 W |
| D6374 150KV | 150 | 0.055 | 39 | 0.227 | 2.75 N·m at 50 A | 146 W |
The highest-Kv motor has the lowest Km; the lowest-Kv motor has the highest and is the larger machine. (These are three different motors, not rewinds of one, so their Km values differ. Within one motor, Km stays fixed as the turns change.) For the D5065, with Kt = 8.27/270 = 0.0306 N·m/A and Rph = 39 mΩ (terminal-to-terminal 78 mΩ), Km = 0.127 N·m/√W. The copper loss for any torque is the same whichever winding it carries. What changes is how that torque is paid for: with a low Kv you pay in volts, with a high Kv you pay in amps.
The bus voltage must cover the back-EMF plus the resistive drop. With id = 0 and space-vector modulation (phase voltage limit Vdc/√3), a first estimate is
| Winding | Ke,LL (V·s/rad) | Kt,pk (N·m/A) | Rph (mΩ) | Ipk (A) | Vdc needed | PCu (W) |
|---|---|---|---|---|---|---|
| 200 Kv | 0.0477 | 0.0413 | 71.1 | 19.35 | 27.4 V (114 %) | 39.9 |
| 270 Kv | 0.0354 | 0.0306 | 39.0 | 26.12 | 20.3 V (85 %) | 39.9 |
| 360 Kv | 0.0265 | 0.0230 | 21.9 | 34.82 | 15.2 V (63 %) | 39.9 |
All three windings dissipate 39.9 W, because Km is the same. The 200 Kv winding cannot do the job: it would need 27.4 V, 114 % of the bus. The 360 Kv winding has plenty of voltage (63 % used) but needs 34.8 A peak, which stresses the inverter and wiring. The stock 270 Kv winding uses 85 % of the bus and 26.1 A, a workable fit with about 15 % in hand. As a rule of thumb I would keep 15–25 % of the bus in reserve for battery sag, the inductive drop and inverter dead time, so a higher bus voltage would make this design more comfortable.
The same logic applies to a gearbox. A ratio N multiplies the torque at the joint and divides the speed, so a high-Kv motor behind a larger ratio can deliver the same joint torque and speed as a low-Kv motor behind a smaller one. Choosing the gear ratio and Kv together is how you move the current/voltage balance to what your battery and controller handle best. Gearbox efficiency is separate and is not included in Kt.
Why a measured Kt comes out lower than the datasheet
- Mechanical and drag losses. Kt defines the electromagnetic torque. A torque sensor on the shaft reads that torque minus bearing and brush friction, windage and the iron-loss drag, which together behave like a roughly constant loss torque. This is what the no-load current I0 represents in the DC motor equations: Tshaft = Kt(I − I0). The apparent constant is therefore Kt(1 − I0/I), which is worst at low current. For the maxon RE 40 (I0 = 68.6 mA) the apparent Kt is 2 % low at the 3.17 A nominal current and 23 % low at 0.3 A. If you measure at the output of a gearbox, its efficiency is a further loss, and cogging adds torque ripple around the average.
- Magnet temperature. NdFeB remanence falls by roughly 0.1 % per °C, so a motor 80 °C above its measurement temperature loses of the order of 10 % of Ke and Kt. A hot motor spins faster per volt and makes less torque per amp. See the NdFeB grade article for the grade-dependent behaviour.
- Saturation. At high current the stator teeth saturate and Kt drops, while open-circuit Ke is unaffected.
- Back-EMF shape. The constants above assume a sine (or ideal trapezoid). Harmonics in the back-EMF add ripple and change average torque per amp, and the same MMF harmonics that cause cogging and rotor loss are involved.
- Reluctance torque. In an interior-magnet machine, torque has a second term from Ld≠Lq, so a single Kt is no longer the whole story.
- Current definition. Peak, RMS and DC-link amps differ by √2 and √3 factors, as the table shows.
Checklist before you trust a number
- Is Ke line-to-line or phase, peak or RMS? Is Kt per peak phase, RMS phase or DC-link ampere?
- Is Kv in rpm/V or rad/s per V, and does it refer to the DC bus voltage?
- Do 9.549/Kv and Ke,LL agree? Do Kt,pk and 0.866 × Ke,LL agree? If not, find the convention that explains the gap.
- At what magnet temperature and current was Kt measured?
- Is the winding compared on Km, not on Kv?
Frequently asked questions
Is the torque constant Kt equal to the back-EMF constant Ke?
In SI units, yes for a brushed DC motor: Kt in N·m/A equals Ke in V·s/rad because electrical power E·I equals mechanical power T·ω. For a three-phase brushless motor the equality holds only when volts and amps are counted consistently. With line-to-line peak Ke and peak phase current, Kt = (√3/2) × Ke, about 0.866 × Ke.
How do I convert Kv to Kt?
With Kv in rpm/V, the line-to-line peak back-EMF constant is 9.549/Kv in V·s/rad. The torque constant is 9.549/Kv N·m/A for a brushed DC motor, 8.27/Kv N·m per peak phase ampere for a sinusoidally driven BLDC or PMSM, and 11.70/Kv N·m per RMS phase ampere.
What does Kv mean for a BLDC motor?
Kv is the no-load speed in rpm per volt of DC bus voltage. It is the inverse of the line-to-line peak back-EMF constant, so a 270 Kv motor turned at 1,000 rpm shows a line-to-line peak of about 3.70 V.
Does a higher Kv motor have more power?
No. Kv is set by the number of turns in the winding. Rewinding with fewer turns raises Kv and lowers Kt and resistance, but leaves the motor constant Km unchanged, so the torque available for a given copper loss does not change. A higher Kv motor reaches a higher speed per volt and needs more current for the same torque.
Why does my measured Kt not match the datasheet?
Datasheet Kt is the cold, low-current, ideal electromagnetic value. Friction and drag losses (which a shaft torque sensor includes), magnet temperature, core saturation at high current, back-EMF harmonics and the current definition (peak, RMS or DC link) can each move it by several percent.
Model a DC motor from its constants
Enter Kt (= Ke), resistance and supply voltage to see the torque–speed line, current and efficiency. The PMSM tool does the same for a three-phase machine. Both are work in progress.References
- maxon group, Motor constants (support article defining speed, torque and generator constants).
- maxon group, RE 40 Ø40 mm, graphite brushes, 150 watt, part 148877. Values quoted at 48 V nominal voltage, read 10 October 2026.
- ODrive Robotics, ODrive Motors (D5065 270KV, D6374 150KV and D5312s 330KV tables and footnotes), read 10 October 2026.
- D. C. Hanselman, Brushless Permanent-Magnet Motor Design, 2nd ed., The Writing Business, 2003.